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| Engine Technology From the novices to the pros, talk about engine technology. Moderated by David Vizard, professional engine developer and well-known technical writer. |
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![]() So since we will have some pressure in the cylinder lets call ir "X" Code:
Equation (((2*14.7)-x)/(14.7-x))^.5
Value of X Evaluated Equation (Flow change)
2.700000000000 1.49164338901763
3.700000000000 1.528516809316678
4.700000000000 1.571623364550171
5.700000000000 1.622754859285078
6.700000000000 1.684488052792302
7.700000000000 1.760681686165901
8.700000000000 1.857417562100671
9.700000000000 1.984943324127921
10.700000000000 2.162174831043965
11.700000000000 2.428991560298224
12.700000000000 2.889636655359978
13.700000000000 3.96232255123179
__________________
Stan Weiss / World Wide Enterprises Offering Performance Software Since 1987 http://users.erols.com/srweiss/index.html Last edited by Stan Weiss; 06-04-2008 at 12:26 PM. |
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Greetings,
Fun topic, this. Some factors that intrigue me: 1.) When the turbo compresses the air to 2 atmospheres, does it do so adiabatically or isothermally, or somewhere in between the two extremes? Gamma could make a big (1.4x) difference in airflow and power. And it is here, for example, that a flowbench and a turbo could create largely divergent results. 2.) The airflow inside the motor as a whole is probably not wholely turbultent, but probably has areas which are somewhat laminar too. Further, the balance between the two would vary as a function of time whithin each combustion cycle and, for turbulent flow, even from cycle to cycle. For this reason, I continue to wonder about the implied mathematical simplicity of thinking that airflow would go solely as pressure ^1/1 or pressure ^1/2. Maybe the best fit for a particular set of condtions would be pressure ^0.634, for instance! Or maybe the fit isn't best captured in this manner. But I speak in the most generall terms here... At any rate, I'll be the first to admit that this is a very weak area of knowledge for me, so I'm looking forward to learning. Best, Mark |
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Yes we talk about flow results in CFM but that is always CFM at a specified condition - usually standard atmospheric. In effect we are back to mass. The flow equations that relate flow to the square root of pressure drop are also stated in terms of mass flow. The actual conditions inside the flowbench will never be atmospheric because there's a pressure drop involved across the test piece so the equations have to correct this volume flow back to mass flow at standard conditions. Nevertheless you are very much on the right lines. The full answer will come from an explanation of why. Dave |
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Greetings,
Volume velocity and mass velocity are interrelated by mass density (rho.) Therefore, divergence between flowbench and global motor behavior for an n-bar boost turbo, ought to be reducible to a matter of rho. Since rho, in turn, depends on the manner of compression, I suspect we're headed back to the question of an adiabatic versus an isothermal process. Dusting off decades worh of cobwebs on this topic speaking for myself, I believe our answer is that the compression is adiabatic, where PV^gamma = constant, and where gamma = 1.4 for a diatomic gas (O2, N2.) And so the question comes full circle to the matter of the fundamental thermodynamics. Change of topic - I'm enjoying the class, but I'd like to know more about its presumptive teacher. Flow Specialist, who are you? Thanks, Mark Last edited by MAP; 06-04-2008 at 06:42 PM. |
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Dave |
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Passing the accumulated knowledge back on still gives me some pleasure and maybe if I ever get a roundtuit I'll write a book but given my propensity for putting things off it'll probably never happen. Dave |
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There, we've found something we can actually agree on. That wasn't so hard after all
![]() Quote:
I wasn't expecting it to turn into a pissing contest quite so soon or I perhaps wouldn't have bothered. I have read plenty of David's work thank you, albeit not the Chevy books, and he doesn't need you to tell me what sort of regard I ought to hold his expertise in. He's known that well enough for 30 years. BTW, the word 'debate' doesn't mean to contradict. It means to discuss, ask further questions. They do say that England and America are two countries divided by a common language so I'll put this down to teething problems of that nature for now and say no more about it. Dave |
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Dear Flow Specialist,
Thanks for the clarifications, but I vote we put this behind us once and for all. If you had explained yourself at the outset, we could have avoided this. Instead, you started with the tone of, "Now class, what do you think about this? And, if you get it wrong, I will correct you and lead you to higher planes of understanding...". This comes across as presumptuous and even a bit egotistical without a proper introduction. In retrospect, I'm sure you can appreciate this. Your background sounds impressive and as I've written before, I look forward to learning from you. So, I hope class is back in session. Best, Mark |
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